Penjelasan dengan langkah-langkah:
1)
[tex] = {( \sqrt{ \frac{ {2}^{x + 2} }{ {4}^{1 - x} } }) }^{ \frac{2}{3} } [/tex]
[tex] = { \sqrt{ \frac{ {2}^{x + 2} }{ {2}^{2(1 - x)} } } }^{ \frac{2}{3} } [/tex]
[tex] = { \sqrt{ \frac{ {2}^{x + 2} }{ {2}^{2 - 2x} } } }^{ \frac{2}{3} } [/tex]
[tex] = \sqrt{ {2}^{x + 2 - (2 - 2x)} }^{ \frac{2}{3} } [/tex]
[tex]= \sqrt{ {2}^{x + 2 - 2 + 2x} }^{ \frac{2}{3} } [/tex]
[tex] = \sqrt{ {2}^{3x} }^{ \frac{2}{3} }[/tex]
[tex] = {( {2}^{ \frac{ \cancel3x}{ \cancel2} }) }^{ \frac{ \cancel2}{ \cancel3} }[/tex]
[tex] = \bold{ {2}^{x} \: (b)} [/tex]
2)
[tex] = \sqrt[3]{ {8}^{3x + 1} } [/tex]
[tex] = \sqrt[ \cancel3]{ {( {2}^{ \cancel3 } )}^{3x + 1} } [/tex]
[tex] = \bold{ {2}^{3x + 1} \: (b)} [/tex]
3)
[tex] = {( {2}^{x + 1}) }^{2} [/tex]
[tex] = {2}^{(x + 1). 2} [/tex]
[tex] = \bold{ {2}^{2x + 2}} [/tex]
4)
[tex] = \sqrt{ {9}^{ \text{x}} } [/tex]
[tex] = \sqrt{ ({3}^{2})^{ \text{x}} } [/tex]
[tex] = \bold{ {3}^{x} \: (b)} [/tex]
5)
[tex] = \sqrt[3]{ \frac{ {3}^{3x + 1} }{ {9}^{2} } } [/tex]
[tex] = \sqrt[3]{ \frac{ {3}^{3x + 1} }{ {3}^{4} } } [/tex]
[tex] = \sqrt[3]{ {3}^{(3x + 1 - 4)} } [/tex]
[tex] = \sqrt[3]{ {3}^{3x - 3} } [/tex]
[tex] = \sqrt[ \cancel3]{ {3}^{ \cancel3(x - 1)} } [/tex]
[tex]= \bold{ {3}^{x - 1} \: (a)} [/tex]
[answer.2.content]
